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x^2+18x+12.5=0
a = 1; b = 18; c = +12.5;
Δ = b2-4ac
Δ = 182-4·1·12.5
Δ = 274
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-\sqrt{274}}{2*1}=\frac{-18-\sqrt{274}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+\sqrt{274}}{2*1}=\frac{-18+\sqrt{274}}{2} $
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